Jeg har fået en funktion, der har formen:
f (x, y) = x2 -3xy + y3 + 3y2
f1 = 2x - 3y, f2 = -3x + 3y2 + 6y
f1 = 0 <=> x = 3/2y
f2 = -3*(3/2y) + 3y2 + 6y = 0
f2 = 3/2y + 3y2 = 0
3/2y + 3y2 = 0 <=> 3y2 = -3/2y
<=> y2 = -1/2y <=> -2 * y2 = y <=> -2 =...
f (x, y) = x2 -3xy + y3 + 3y2
f1 = 2x - 3y, f2 = -3x + 3y2 + 6y
f1 = 0 <=> x = 3/2y
f2 = -3*(3/2y) + 3y2 + 6y = 0
f2 = 3/2y + 3y2 = 0
3/2y + 3y2 = 0 <=> 3y2 = -3/2y
<=> y2 = -1/2y <=> -2 * y2 = y <=> -2 =...